To determine Young's modulus of a wire,the formula is $Y = \frac{F}{A} \cdot \frac{L}{\Delta L}$,where $F/A$ is the stress and $L/\Delta L$ is the reciprocal of strain. The conversion factor to change $Y$ from $CGS$ to $MKS$ system is:

  • A
    $1$
  • B
    $10$
  • C
    $0.1$
  • D
    $0.01$

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Similar Questions

State whether the following statements are true or false:
$(a)$ $A$ dimensionally incorrect equation can be correct.
$(b)$ $1 \ AU = 9.46 \times 10^{15} \ m$
$(c)$ The dimensional formula of force and stress are the same.
$(d)$ The dimensions of a physical quantity are different in different systems of units.

The fundamental unit which has the same power in the dimensional formula of surface tension and viscosity is

Match the physical quantities in List-$I$ with their dimensional formulas in terms of mass $(M)$, length $(L)$, time $(T)$ and electric current $(A)$ given in List-$II$.
List-$I$List-$II$
$(a)$ Torque$(i)$ $[M^{-1}L^{-2}T^4A^2]$
$(b)$ Gravitational constant(ii) $[M^1L^2T^{-1}]$
$(c)$ Capacitance(iii) $[M^{-1}L^3T^{-2}]$
$(d)$ Planck's constant(iv) $[M^1L^2T^{-2}]$

Match the physical quantities given in List-$I$ with dimensions expressed in terms of mass $(M)$, length $(L)$, time $(T)$ and electric current $(A)$ given in List-$II$.
List-$I$List-$II$
$(a)$ Torque$(i)$ $[M^{-1}L^{-2}T^4A^2]$
$(b)$ Gravitational constant(ii) $[M^1L^2T^{-1}]$
$(c)$ Capacitance(iii) $[M^{-1}L^3T^{-2}]$
$(d)$ Planck’s constant(iv) $[M^1L^2T^{-2}]$

Which of the following pairs does not have the same dimensions?

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